SnCl2 is oxidised to SnCl4, then which of the following property is less for the product as compared to reactant?

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${SnCl}_{2}$ is oxidised to $S n C l_{4}$ , then which of the following property is less for the product as compared to reactant?

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Reducing property

Tendency of hydrolysis

Covalent character

Stability of oxidation state of Sn

answer is D.

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Detailed Solution

a greater degree of stability Two more electrons are removed from $Sn (+ 2)$ to get the more stable $Sn (+ 4)$ .
${Sn}^{2 +}$ is decreasing. So, ${Sn}^{2 +}$ is reducing.

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