${\mathrm{SnCl}}_2$ is oxidised to $SnC{l}_4$, then which of the following property is less for the product as compared to reactant?

a greater degree of stability Two more electrons are removed from $\mathrm{Sn} (+2)$ to get the more stable $\mathrm{Sn} (+4)$.
${\mathrm{Sn}}^{2+}$ is decreasing. So, ${\mathrm{Sn}}^{2+}$ is reducing.