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$S O_{2}$ is generally manufactured by burning iron pyrites $(F e S_{2}) .$ What is the weight of oxygen (in grams) required for oxidizing $60 g m s of F e S_{2}$
At wts : Fe = 56, S = 32, O = 6

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answer is 44.

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Detailed Solution

$4 F e S_{2} + 11 O_{2} \to 2 F e_{2} O_{3} + 8 S O_{2}$

480 352
60 ___ ?
$\frac{60 \times 352}{480} = 44$

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