Q.

SO3 gas is entering the environment at a constant rate of 6.93 x 10-6 g / L / day due to emission of polluting gases from thermal power plant at Kota but at the same time it is decomposing and following first-order kinetics with half-life of 100 days. Based on these details, select the correct statement(s) from the following.

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a

Concentration of SO3 in Kota is 1.25 x10-5M (assume SO3 present in air reaches
steady state)

b

If SO3 emission is stopped, then after 1000 days, its concentration will reduce to 1.22 x 10-8M

c

An industry is manufacturing H2SO4 at the rate of 980 kg per day with the use of SO3 in air and it should use 8 x105 L air per day

d

If 103L of air is passed through 1L pure water (assuming all SO3 is dissolved in it) and the resulting solution is titrated against 1N NaOH solution, 15 ml of NaOH solution is required to reach the end point

answer is A, D.

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Detailed Solution

a) For steady state, 6.93×10680=0.693100×SO3
[SO3] = 1.25 x 105M
 b) neqSO3=ncqNaOH1.25×105×103×2=VNaOH×1
VNaOH = 2.5 x 10-2 L = 25 mL
c) Mole of SO3 needed = =980×10398=104
Air needed = 1041.25×105=8×108L
d) 1000 days = 10 t1/2
SO3=1.25×105210=1.25×108M

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