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Sodium (atomic number = 11) belongs to first group and third period of modern periodic table. Which of the following is/are correct?

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Direction of angular momentum of an electron in the first orbit of $N a^{+ 10}$ ion is given by Bohr’s theory.

Second ionization energy is very higher than third ionization energy of Sodium atom due to stable inert gas configuration of sodium(I) ion.

Sodium vapour emits two yellow lines of close wavelengths while excitation of 3s electron.

If there are no electron-electron repulsions and no spin associated with nucleus and electrons, the energy of highest energy electron in the ground state of isolated sodium atom is $(- \frac{13.6}{9}) \times 121 e V .$

answer is D.

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Excitation absorbs wavelength

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