Sodium cyclopentadienide exists as NaC5H5.(THF)x. To determine the value of x, an experiment is performed by dissolving a small amount of the sample in water and titrating the formed NaOH with standard HCl solution.NaC5H5.(THF)x+H2O→ NaOH+C5H6+x THF Molecular formula of THF is C4H8O .The following result data was collected from such an experiment: Trial 1Trial 2Weight of NaC5H5.(THF)x0.52 g0.41 gVolume of 0.1 M HCl required to titrate NaOH 10 mL 7.88 mLThe value of x is_____.[Atomic weights: H = 1, C = 12, Na = 23]

NaC5H5.(THF)x+H2O→ NaOH+C5H6+x THFnNaC5H5.(THF)x=nNaOH⇒0.5288+72x=10×0.11000⇒x=6

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Sodium cyclopentadienide exists as $N a C_{5} H_{5} . {(T H F)}_{x}$ . To determine the value of x, an experiment is performed by dissolving a small amount of the sample in water and titrating the formed NaOH with standard HCl solution.
$N a C_{5} H_{5} . {(T H F)}_{x} + H_{2} O \overset{}{\to} N a O H + C_{5} H_{6} + x T H F$
Molecular formula of THF is $C_{4} H_{8} O$ .
The following result data was collected from such an experiment:

Trial 1
Trial 2
Weight of $N a C_{5} H_{5} . {(T H F)}_{x}$
0.52 g
0.41 g
Volume of 0.1 M HCl required to titrate NaOH

10 mL

7.88 mL
The value of x is_____.
[Atomic weights: H = 1, C = 12, Na = 23]

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answer is 6.

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$N a C_{5} H_{5} . {(T H F)}_{x} + H_{2} O \overset{}{\to} N a O H + C_{5} H_{6} + x T H F$

$n_{N a C_{5} H_{5} . {(T H F)}_{x}} = n_{N a O H} \Rightarrow \frac{0.52}{88 + 72 x} = \frac{10 \times 0.1}{1000} \Rightarrow x = 6$

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