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Sodium metal crystallizes in a body centred cubic lattice with a unit cell edge of 4.29 A. The radius of sodium atom is approximately

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3.22 $Å$

5.72 $Å$

1.86 $Å$

0.93 $Å$

answer is A.

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Detailed Solution

In a body centred cubic lattice, atoms touch each other along the body diagonal of the cube. Hence

$4 r = \sqrt{3} a$ or $r = (\sqrt{3} / 4)$ $a = (\sqrt{3} / 4) (4.29 Å) = 1.86 Å$

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