Sodium palmitate is a major constituent in soap. When an aqueous solution of sodium paimitate having $1 k g$ of solvent is analysed for its boiling point, following data is obtained.
Moles Boiling Point
$0$ $100 ° C$
$0.02$ $100.0372 ° C$
$0.04$ $100.0744 ° C$
$0.05$ $100.093 ° C$
$0.06$ $100.1 ° C$
$0.08$ $100.12 ° C$
Identify the option(s) which is/are correct.

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

Aqueous mixture of sodium palmitate having concentration equal to $0.07 M$ will be heterogeneous.

Osmotic pressure at $0.08 M$ at $300 K$ will be $1.9704 a t m$ .

At $0.4 M$ concentration, the solution is homogeneous.

The CMC value of sodium palmitate should be less than $0.06 M$ .

answer is A, B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

$A T_{b} = K_{b} m$

$\frac{03.72}{02} = K_{b}$

$K_{b} = 1.86$

$Δ T_{b_{2}} = K_{b} m = 0.04 \times 1.86 = 0.0744$

$Δ T_{b_{3}} = 1.86 \times 0.05 = 0.093$

$Δ T_{b} = 1.86 \times 0.06 = 0.1116$

Hence, options A and B are correct.

Watch 3-min video & get full concept clarity

JEE

NEET

Foundation JEE

Foundation NEET

CBSE