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Sodium palmitate is a major constituent in soap. When an aqueous solution of sodium paimitate having $1 k g$ of solvent is analysed for its boiling point, following data is obtained.
Moles Boiling Point
$0$ $100 ° C$
$0.02$ $100.0372 ° C$
$0.04$ $100.0744 ° C$
$0.05$ $100.093 ° C$
$0.06$ $100.1 ° C$
$0.08$ $100.12 ° C$
Identify the option(s) which is/are correct.

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Aqueous mixture of sodium palmitate having concentration equal to $0.07 M$ will be heterogeneous.

Osmotic pressure at $0.08 M$ at $300 K$ will be $1.9704 a t m$ .

At $0.4 M$ concentration, the solution is homogeneous.

The CMC value of sodium palmitate should be less than $0.06 M$ .

answer is A, B.

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Detailed Solution

$A T_{b} = K_{b} m$

$\frac{03.72}{02} = K_{b}$

$K_{b} = 1.86$

$Δ T_{b_{2}} = K_{b} m = 0.04 \times 1.86 = 0.0744$

$Δ T_{b_{3}} = 1.86 \times 0.05 = 0.093$

$Δ T_{b} = 1.86 \times 0.06 = 0.1116$

Hence, options A and B are correct.

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