Sodium thiosulphate reacts with iodine to give iodide and tetrathionate. In this reaction S₂O₃^2- undergoes

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Oxidation

Reduction

Disproportionation

Comproportionation

answer is A.

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Detailed Solution

$large mathop {2{S_2}}limits^{ + 2} O_3^{ - 2}; + ;{I_2}; to ;mathop {{S_4}}limits^{ + 2.5} O_6^{ - 2}; + ;2{I^ - }$
Oxidation state of 'S' in $large {S_2}O_3^{ - 2}$ increase from +2 to +2.5
$large therefore ;{S_2}O_3^{ - 2};$ undergoes Oxidation

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