Q.

Solid NH4Ion rapid heating in a closed vessel at 357° C develops pressure of 300 mm Hg owing to partial decomposition ofNH4 I into NH3 and HI but .he pressure gradually increases further (when the excess solid residue remains in the vessel) owing to the dissociation of HI. Calculate the final pressure (in mm of Hg) developed at equilibrium. Kp for HI dissociation is 2 at 357° C. HI12H2+12I2.

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answer is 900.

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Detailed Solution

In the reaction ammonia is obtained;

NH4I(s)    NH3(g)    +HI(g)                           150mm    150mm    KP=150×150HI               12H2     +    12    I2    150P          P2                  P2    

P2150P=2=KPP=6004P5P=600P=120PHI=150120=30150×150=PNH3×30PNH3=750mm Final total P=PNH3+PHI+PH2+PI2=750+30+60+60=900mm

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