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Q.

Solubility of ammonium chloride at $293 K$ is $37 g$ . The mass of ammonium chloride that would be needed to make a saturated solution in $10 g$ of water at $293 K$ is

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a

37 g

b

3.7 g

c

0.37 g

d

6.4 g

answer is B.

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Detailed Solution

The mass of ammonium chloride that would be needed to make a saturated solution in

10 g

of water at

293 K

is

3.7 g

.
Solubility of solid components in liquid is dependent on the polarity. Polar solid is soluble in polar solvent and non-polar solid is soluble in the non-polar solvent. Maximum amount of solute that can be dissolved in 100 g of a solvent at a particular specified temperature is known as the solubility of the solute in that solvent at the specified temperature.
Solubility of ammonium chloride

= 37 g

So in

100 g

of water, mass of ammonium chloride dissolved is

37 g

∴ In

10 g

of ammonium chloride to obtain a saturated solution at

293 K

\Rightarrow

\frac{37 \times 10}{100}

\Rightarrow

3.7 g

Thus

3.7 g

ammonium chloride would be needed to produce a saturated solution of ammonium chloride in

10 g

of water at

293 K

.

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