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Q.

Solubility of ammonium chloride at 293 K is 37 g. The mass of ammonium chloride that would be needed to make a saturated solution in 10 g of water at 293 K is


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a

37 g

b

3.7 g

c

0.37 g

d

6.4 g 

answer is B.

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Detailed Solution

The mass of ammonium chloride that would be needed to make a saturated solution in 10 g of water at 293 K is 3.7 g.
Solubility of solid components in liquid is dependent on the polarity. Polar solid is soluble in polar solvent and non-polar solid is soluble in the non-polar solvent. Maximum amount of solute that can be dissolved in 100 g of a solvent at a particular specified temperature is known as the solubility of the solute in that solvent at the specified temperature.
Solubility of ammonium chloride =37 g
So in 100 g of water, mass of ammonium chloride dissolved is 37 g
 ∴ In 10 g of ammonium chloride to obtain a saturated solution at 293 K ⇒ 37×10100
⇒ 3.7 g
Thus 3.7 g ammonium chloride would be needed to produce a saturated solution of ammonium chloride in 10 g of water at 293 K.
 
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