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Q.

Solubility of AgCl in pure water is 10-5 mol/litre at 25° C then, calculate solubility of AgCl in 0.1 M aqueous solution of KCl at 25° C.

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a

10−4mol/ litre 

b

10−7mol/ litre 

c

10−9mol /litre 

d

10−5mol/ litre 

answer is A.

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Detailed Solution

Ksp=10−10

=0.1×x

x=10−9

Hence, option A is correct.

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