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Q.

Solubility product of a sparingly soluble salt, ${AB}_{2}$ is $1.08 \times 10^{- 25}$ . Molar solubility of ${AB}_{2}$ will be

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a

$10^{- 12}$

b

$10^{- 9}$

c

$27 \times 10^{- 6}$

d

$3 \times 10^{- 9}$

answer is B.

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Detailed Solution

$4 S^{3} = 108 \times 10^{- 27}$
$S^{3} = 27 \times 10^{- 27}$
$S = 3 \times 10^{- 9}$

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Solubility product of a sparingly soluble salt, AB2 is 1.08×10−25. Molar solubility of AB2 will be