Solubility product of AgCl is $1.96 \times 10^{- 10} M^{2}$ . Weight of AgCl dissolved in 696.8 ml of saturated solution is $x \times 10^{- 4} g$ . Value of ‘x’ is (nearest integer) (GFW of AgCl = 143.5g)

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Detailed Solution

$S^{2} = 1.96 \times 10^{- 10};$

$\begin{array}{l} S = 1.4 \times 10^{- 5} M; \\ 1.4 \times 10^{- 5} = \frac{w}{143.5} \times \frac{1000}{696.8} \\ w = 1.4 \times 10^{- 3} \\ w = 14 \times 10^{- 4} \end{array}$

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