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Q.

Solubility product of silver bromide is 5 × 10–13. The quanitity of potassium bromide (molar mass taken as 120 g mol–1) to be added to 1 litre of 0.05 M solution of silver nitrate to start the precipitation of AgBr is :

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a

5.0\, \times \,{10^{ - 8}}\,g

b

\large 6.2\, \times \,{10^{ - 5}}  g

c

1.2\, \times \,{10^{ - 10}}\,g

d

1.2\, \times \,{10^{ - 9}}\,g

answer is D.

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Detailed Solution

[Ag+] = 5 x 10-2

For precipitation, KIP≥Ksp

OR [Ag+] [Br-] = 5 x 10-13

\Rightarrow \left[ {B{r^ - }} \right] = \frac{{5 \times {{10}^{ - 13}}}}{{5 \times {{10}^{ - 2}}}} = {10^{ - 11}}
{n_{B{r^ - }}} = {10^{ - 11}}
\frac{m}{{120}} = {10^{ - 11}}

m = 1.2 x 10-9 g

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