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Solubility product of silver bromide is 5 × 10^–13. The quanitity of potassium bromide (molar mass taken as 120 g mol^–1) to be added to 1 litre of 0.05 M solution of silver nitrate to start the precipitation of AgBr is :

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$5.0\, \times \,{10^{ - 8}}\,g$

$\large 6.2\, \times \,{10^{ - 5}}$ g

$1.2\, \times \,{10^{ - 10}}\,g$

$1.2\, \times \,{10^{ - 9}}\,g$

answer is D.

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Detailed Solution

[Ag⁺] = 5 x 10^-2

For precipitation, K_IP $\geq$ K_sp

OR [Ag⁺] [Br^-] = 5 x 10^-13

\Rightarrow \left[ {B{r^ - }} \right] = \frac{{5 \times {{10}^{ - 13}}}}{{5 \times {{10}^{ - 2}}}} = {10^{ - 11}}

m = 1.2 x 10^-9 g

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