Solubility product of sparingly soluble salt X2Y3 is 1.08×10-18 M5. Molar solubility of X2Y3 will be

X2Y3⇌2X+32s+3Y-23sKsp=2s23s3Ksp=108 s51.08×10-18=108 s5s5=10-20s=10-4M

Solubility product of sparingly soluble salt X2Y3 is 1.08×10-18 M5. Molar solubility of X2Y3 will be

X2Y3⇌2X+32s+3Y-23sKsp=2s23s3Ksp=108 s51.08×10-18=108 s5s5=10-20s=10-4M

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Solubility product of sparingly soluble salt $(X_{2} Y_{3})$ is $1.08 \times 10^{- 18} M^{5} .$ Molar solubility of $X_{2} Y_{3}$ will be

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$10^{- 10} M$

$10^{- 2} M$

$10^{- 8} M$

$10^{- 4} M$

answer is B.

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Detailed Solution

$X_{2} Y_{3} ⇌ \underset{2 s}{2 X^{+ 3}} + \underset{3 s}{3 Y^{- 2}}$

$K_{sp} = {(2 s)}^{2} {(3 s)}^{3}$

$K_{sp} = 108 s^{5}$

$1.08 \times 10^{- 18} = 108 s^{5}$

$s^{5} = 10^{- 20}$

$s = 10^{- 4} M$

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Solubility product of sparingly soluble salt X2Y3 is 1.08×10-18 M5. Molar solubility of X2Y3 will be

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Solubility product of sparingly soluble salt $(X_{2} Y_{3})$ is $1.08 \times 10^{- 18} M^{5} .$ Molar solubility of $X_{2} Y_{3}$ will be