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Q.

Solute A associates in water. When 0.7 g of solute A is dissolved in 42.0 g of water, it depresses the freezing point by 0.2°C. The percentage association of solute A in water, is [Given : Molar mass of A = 93 g mol^–1. Molal depression constant of water is 1.86 K kg mol^–1]

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a

50 %

b

60 %

c

70 %

d

80 %

answer is D.

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Detailed Solution

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$\begin{aligned} ΔT = {ik}_{f} \times m \\ 0.2 = i \times 1.86 \times \frac{0.7}{93} \times \frac{1000}{42} \\ i = \frac{0.2 \times 93 \times 6}{1.86 \times 100} \\ i = 0.60 \\ 2 A ⇌ A_{2} \\ 1 - α \\ i = 1 - \frac{α}{2} \\ i = 1 - \frac{α}{2} \\ 1 - \frac{α}{2} = 0.60 \\ 1 - 0.60 = \frac{α}{2} \end{aligned} α = 0.80$

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