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Q.

Solution of the differential equation (siny+y(1+1x))dx+(x(1+cosy)+lnx)dy=0 is

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a

ysiny+xyln|x|=c

b

xy+yln|x|+xsiny=c

c

xy+yln|x|xsiny=c

d

y+siny+xyln|x|=c

answer is A.

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Detailed Solution

(siny+y(1+1x))dx+(x(1+cosy)+lnx)dy=0

sinydx+xcosydy+xdy+ydx+yxdx+lnxdy=0

d(x.siny)+d(xy)+d(y.lnx)=0

x.siny+xy+y.lnx=c

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