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Q.

Solutionof7sin2x+3cos2x=4is

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a

nπ±π/2

b

nπ±π/4

c

nπ±π/3

d

nπ±π/6

answer is D.

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Detailed Solution

7sin2x+3cos2x=47sin2x+33sin2x=44sin2x=1sin2x=1/4=(1/2)2=sin2(π/6)x=nπ±(π/6),nZ.

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