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Solutions containing 23g HCOOH is/are:

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$50 g of 25 % (\frac{w}{w}) HCOOH$

$46 g of 70 % (\frac{w}{V}) HCOOH (d_{solution} = 1 .40 g / ml)$

$46 g of 5 MHCOOH (d_{solution} = 1 g / ml)$

$50 g of 10 MHCOOH (d_{solution} = 1 g / ml)$

answer is A, B.

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Detailed Solution

$1 ml wt \to 1 .40; 100 ml wt \to 140 gr sol . 70 % \to 70 gr in 100 ml; 70 gr ∴ 50 %; 46 gr \to 23 gr HCOOH$

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