Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5

Q.

Solve in nonzero real numbers the system of equations {7x27y=2x29y21x=2y2 Find the value of  y?

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

answer is 2.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

First, we will consider the system as a system with the unknowns 1xand1y . This is a linear system, so rather easy to solve. We obtain

28x=x2+3y2and36y=3x2+y2.

Multiplying the first equation by x and the second one by y we obtain the equivalent system
{x3+3xy2=283x2y+y3=36.
We recognize the terms of the expansion of  (x+y)3and(xy)3 By adding and subtracting the equations, we obtain another form of the system
{(x+y)3=64(xy)3=8

This is quite easy to solve, since it is equivalent to x+y=-4 and x-y=2, then x=-1 and y=-3.

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon