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Q.

Solve in nonzero real numbers the system of equations {7x27y=2x29y21x=2y2 Find the value of  y?

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answer is 2.

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Detailed Solution

First, we will consider the system as a system with the unknowns 1xand1y . This is a linear system, so rather easy to solve. We obtain

28x=x2+3y2and36y=3x2+y2.

Multiplying the first equation by x and the second one by y we obtain the equivalent system
{x3+3xy2=283x2y+y3=36.
We recognize the terms of the expansion of  (x+y)3and(xy)3 By adding and subtracting the equations, we obtain another form of the system
{(x+y)3=64(xy)3=8

This is quite easy to solve, since it is equivalent to x+y=-4 and x-y=2, then x=-1 and y=-3.

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