Solve the equation : $3 (x + 2) – 2 (x – 1) = 7$

Given: $3 (x + 2) – 2 (x – 1) = 7$

On simplifying the brackets, we get:

$$\begin{gathered} => 3 \times x + 3 \times 2 – 2 \times x + 2 \times 1 = 7 \\ => 3x + 6 – 2x + 2 = 7 \\ => 3x – 2x + 6 + 2 = 7 \\ => x + 8 = 7 \end{gathered}$$

Subtracting 8 from both sides, we get:

$$\begin{gathered} => x + 8 – 8 = 7 – 8 \\ => x = -1 \end{gathered}$$