Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5

Q.

Solve the following equation for x.


x+3 x2 1x x = 17 4 ;x0,2


see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya

a

x is 4, 2 9

b

x is 5, 2 9

c

x is 4, 1 9

d

x is 4, 2 7  

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Given equation is x+3 x2 1x x = 17 4 ;x0,2.
In quadratic equation, a x 2 +bx+c=0(a0) Discriminant, D= b 2 4ac Root of quadratic equation, x= b± D 2a .
On simplifying the given equation we get,
x+3 x2 1x x = 17 4 x 2 +3xx+ x 2 +22x x 2 2x = 17 4 4 2 x 2 +2 =17 x 2 2x 8 x 2 +8=17 x 2 34x 9 x 2 34x8=0 Now let us find the roots using the quadratic formula.
x= (34)± (34) 2 4(9)(8) 2(9) x= 34± 1444 18 x= 34±38 18 x= 34+38 18 , 3438 18 x=4, 2 9
The value of x is 4, 2 9 .
The correct option is (1).
 
Watch 3-min video & get full concept clarity

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon
Solve the following equation for x. x+3 x−2 − 1−x x = 17 4 ;x≠0,2