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Q.


Solve the following linear equations 3t−2 4 − 2t+3 3 = 2 3 −t  .

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a

t=2

b

t=5

c

t=13

d

t=7  

answer is A.

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Detailed Solution


Given equation is 3t−2 4 − 2t+3 3 = 2 3 −t  .
Solving for the value of t.
Transposing t to the left-hand side.
⇒ 3t−2 4 − 2t+3 3 +t= 2 3  
Taking the LCM of (4, 3).
⇒ 3 3t−2 −4 2t+3 +12t 12 = 2 3 ⇒9t−6−8t−12+12t= 12×2 3 ⇒13t−18=8 ⇒t= 26 13 ⇒t=2  
Hence, value of variable t is 2.
Correct option is 1.
 
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