Q.

Solve the following pair of linear equations by the substitution method: 0.2x+0.3y=1.3;0.4x+0.5y=2.3.


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a

x=1,y=-2

b

x=6,y=-7

c

x=5,y=1

d

x=2,y=3 

answer is D.

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Detailed Solution

Given equations are, 0.2x+0.3y=1.3;0.4x+0.5y=2.3.
Considering first equation,
0.2x+0.3y=1.3…………….(1)
x=1.3-0.3y0.2……………..(2)
And considering second equation,
0.4x+0.5y=2.3………………(3)
Substitute x=1.3-0.3y0.2  in equation (3),
0.4×(1.3-0.3y0.2)+0.5y=2.3 0.2×(1.3-0.3y)+0.5y=2.3
2.6-0.6y+0.5y=2.3 -0.1y=-0.3 y=3 Substitute y=3 in equation (2),
0.2x+0.3(3)=1.3
x=1.3-0.90.2 x=2 Thus, the solution is x = 2 and y = 3.
Therefore, option (4) is correct.
 
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