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Q.

Solve the following quadratic equations by factorization:


4 x 3= 5 2x+3 ,x0, 3 2  


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a

2, -2

b

1, -2

c

3, -4

d

4, -2 

answer is B.

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Detailed Solution

Given,
4 x 3= 5 2x+3 ,x0, 3 2   4 x 3= 5 2x+3 43x x = 5 2x+3  
Cross-multiply and solve,
  (43x)(2x+3)=5x 8x6 x 2 +129x=5x 6 x 2 8x12+9x+5x=0 6 x 2 +6x12=0  
Divide both sides by 6,
1 6 6 x 2 +6x12 = 1 6 ×0 x 2 +x2=0   x 2 +2xx2=0 x(x+2)1(x+2)=0 (x1)(x+2)=0   x-1=0 or x+2=0
x=1,-2
Hence, the correct option is 2.
 
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