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Q.

Solve the following system of linear equations graphically.


3x+2y4=0 2x3y7=0


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a

x=2 and y=-1

b

x=3 and y=-1

c

x=-2 and y=-1

d

x=2 and y=1 

answer is A.

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Detailed Solution

Given equations are,
3x+2y4=0 …………(1)
2x3y7=0 ……………(2)
To get the values of x and y, solve equation (1).
3x+2y=4 3x=42y x= 42y 3 …………….(3)
In the equation(3), enter y = 0.
x= 42 0 3 x= 4 3 Now enter y=1 into the equation (3)
x= 42 1 3 x= 42 3 x= 2 3 Now enter y= 3 into the equation (3)
x= 42 3 3 x= 46 3 x= 2 3
 

x

4 3

2 3

2 3

y

0

1

3

 To get the values of x and y, solve equation (2).
3y=72x 3y=2x7 y= 2x7 3 ……………..(4)
Enter x=0 into the equation (4).
y= 2 0 7 3 y= 7 3 Now enter x= 4 into the equation (4).
y= 2 4 7 3 y= 87 3 y= 1 3 Now enter x= 5 into the equation (4).
y= 2 5 7 3 y= 107 3 y= 3 3 y=1
   

x

0

4

5

y

7 3

1 3

1

 Form the graph for given equations 3x+2y4=0 and 2x3y7=0 with the above obtained x and y values.
Question Image From the graph, the solution of the given equations is x=2 and y=-1.
The correct option is (1).
 
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