Q.

Some amount of dichloromethane (CH2Cl2)  is added to 671.141 ml of chloroform (CHCl3)  to prepare 2.6×103M solution of CH2Cl2 (DCM). The concentration of DCM is ____________ppm
 (by mass) Given :
 Atomic mass: C = 12 H = 1
 Cl = 35.5 Density of   = 1.49 g cm-3

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answer is 221.

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Detailed Solution

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wt of solution =  671.141(ml)×1.49g/ml
=1000gwt  of   solute=2.6×103×85(CH2Cl2)=221×103g=wt  of  solute(g)wt  of  solution(g)×106ppm=221×103103×106=221ppm

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