Some energy levels of a molecule are shown in the figure. The ratio of the wave lengths $r = λ 1 λ 2$ is given by

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r = 23

r = 43

r = 13

r = 34

answer is D.

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Detailed Solution

$\frac{1}{λ_{1}} \propto [- E - (- 2 E)] = E - - - - (1)$

$\frac{1}{λ_{2}} \propto [- E - (- \frac{4}{3} E)] = \frac{E}{3} - - - - (2)$
So, $\frac{(1)}{(2)} gives \frac{λ_{2}}{λ_{1}} = 3 \Rightarrow r = \frac{λ_{1}}{λ_{2}} = \frac{1}{3}$

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