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Q.

Some older emergency oxygen masks containing potassium superoxide, KO2 which reacts with CO2 and water in exhaled air to produce oxygen according to the given equation. If a person exhales 0.667 g of CO2 per minute, how many grams of KO2 are consumed in 5.0 minutes?
4KO2+2H2O+4CO2⟶4KHCO3+3O2

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a

10.7

b

0.0757

c

1.07

d

5.38

answer is D.

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Detailed Solution

 1 min -0.667 gm

5 min-  ?⇒5x0.667=3.335 gm

no. of moles of CO2  =wtg.mwt =3.33544=0.075795

Moles of KO2 consumed =0.075795

mass of KO2 =?

No. of moles of KO2 =wtg.mwt

0.075795 =x71

x =0.075795 x 71 =5.38 gms

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