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Some older emergency oxygen masks contains potassium superoxide, KO₂ which reacts with CO₂and water present in exhaled air to produce oxygen according to the given equation. If a person exhales 0.667 g of CO₂ per minute, how many grams of KO₂ are consumed in 5.0 minutes ?
$4 {KO}_{2} + 2 H_{2} O + 4 {CO}_{2} ⟶ 4 {KHCO}_{3} + 3 O_{2}$

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10.7

0.0757

5.38

1.07

answer is D.

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Detailed Solution

CO₂exhaled in 5 minutes = 0.667 x 5 = 3.33 g

moles of CO₂ = $\frac{3.33}{44} = 0.0756 mole$

moles of KO₂ consumed = 0.0756 moles (according to equation reaction)
mass of KO₂ consumed = 0.0756 x 71 = 5.38 g
(Since Mw of KO₂ =71 g)

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