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Q.

Some rocket engines use a mixture of Hydrazine,  N2H4 and Hydrogen peroxide, H2O2 as the propellant. The reaction is given by the following equation: N2H4(l)+2H2O2 (l)N2(g)+4H2O
How much of the excess reactant, remains unchanged ? When 0.750 mol of  N2H4 is mixed with 17 g of H2O2?

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a

0.25molN2H4

b

16g of N2H4

c

0.25molH2O2

d

8.5gH2O2

answer is A.

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Detailed Solution

N2H4(l)+2H2O2 (l)N2(g)+4H2O

1 mole of   N2H4    -    2 moles of  H2O2
                            32 g       -             68 g
(0.75 moles)  24 g  -             51 g  
                 8 g         -             17 g
So excess reagent is N2H4 and remain unchanged is  248=16g.
 

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