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Q.

Some standard electrode potentials at 298 K are given below.

Pb2+ / Pb -0.13V
Ni2+ / Ni -0.24V
Cd2+ / Cd -0.40V
Fe2+ / Fe -0.44V

To a solution containing 0.001 M of X2+ and 0.1 M of Y2+, the metal rods X and Y are inserted (at 298 K) and connected by a conducting wire. This resulted in dissolution of X. The correct combination(s) of X and Y respectively, is(are)
(Given Gas constant, R = 8.314 JK-1 mol-1, Faraday constant, F = 96500 C mol-1)

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a

Ni and Pb

b

Cd and Ni

c

Cd and Fe

d

Ni and Fe

answer is A, B, C.

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Detailed Solution

x→x+2+2e−y+2+2e−→y(s)Ecell =Ecell 0=0.062log⁡x+2y+2

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