Some standard electrode potentials at 298 K are given below.
Pb²⁺ / Pb -0.13V
Ni²⁺ / Ni -0.24V
Cd²⁺ / Cd -0.40V
Fe²⁺ / Fe -0.44V
To a solution containing 0.001 M of X²⁺ and 0.1 M of Y²⁺, the metal rods X and Y are inserted (at 298 K) and connected by a conducting wire. This resulted in dissolution of X. The correct combination(s) of X and Y respectively, is(are)
(Given Gas constant, R = 8.314 JK^-1mol^-1, Faraday constant, F = 96500 C mol^-1)

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Ni and Pb

Cd and Ni

Cd and Fe

Ni and Fe

answer is A, B, C.

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Detailed Solution

$\begin{array}{l} x \to x^{+ 2} + 2 e^{-} \\ y^{+ 2} + 2 e^{-} \to y_{(s)} \\ E_{cell} = E_{cell}^{0} = \frac{0.06}{2} \log \frac{x^{+ 2}}{y^{+ 2}} \end{array}$

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Pb²⁺ / Pb	-0.13V
Ni²⁺ / Ni	-0.24V
Cd²⁺ / Cd	-0.40V
Fe²⁺ / Fe	-0.44V