Some Statements regarding the reaction are given below.

Select the correct statement( s ). ( If needed, consider major) 

$Q_2$ is a binary mixture and is optically inactive due to external compensation

In the P to $Q_1$ Conversion step the $B{r}_2$ adds on P in a syn manner and the intermediate formed is a cyclic brominium ion.

$Q_1$ is a pure compound and optically inactive due to internal compensation 

P is a trans-alkene