Some statements regarding the reaction:
are given below. Select the correct statement(s)

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$Q_{2}$ is a binary mixture and is optically inactive due to external compensation.

In the P to $Q_{1}$ conversion step the ${Br}_{2}$ adds on P in a syn manner and the intermediate formed is a cyclic brominium ion.

$Q_{1}$ is a pure compound and optically inactive due to internal compensation

P is a trans-alkene

answer is A, D.

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Detailed Solution

Addition of ${Br}_{2}$ on an alkene is a trans-addition. $Q_{1}$ is a binary mixture and is optically inactive due to external compensation. Note that the alkene P formed (MeCH = CHEt) is an unsymmetrical alkene and hence anti addition of ${Br}_{2}$ upon it will not yield meso-product.

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