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Q.

Sound waves of frequency 660 Hz fall normally on a perfectly reflecting wall. The shortest distance from the wall at which the air particles have maximum amplitude of vibration is x×103  metres. Find x.

[Speed of sound = 330 m/s]

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answer is 125.

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Detailed Solution

c=vλλ=cv=330660=0.5 m

Shortest distance from the wall at which air particles have the maximum amplitude of vibration  
 =λ/4=0.54=0.125m

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