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Source and observer both start moving simultaneously from origin, one along X-axis and the other along Y-axis with speed of source equal to twice the speed of observer. The graph between the apparent frequency (n' ) observed by observer and time t would be : (n is the frequency of the source)

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answer is B.

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Detailed Solution

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n¹ = $(\frac{V - V_{o} \sin α}{V - V_{s} \cos α})$ n tan $α = \frac{1}{2}$ const and n¹ remains const and n¹ < n.
tan $α = \frac{1}{2}$ n¹ < n

so. graph. must be

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