Q.

‘sp2d’ hybridization is observed in

Moderate

Want to Fund your own JEE / NEET / Foundation preparation ??

Take the SCORE scholarship exam from home and compete for scholarships worth ₹1 crore!*
An Intiative by Sri Chaitanya

a

[Cu(NH3)4]SO4

b

K2[Ni(CN)4]

c

K2[NiCl4]

d

Na2[CuCl4]

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

The hybridization should be dsp2.

The Cu atom is in form of Cu+2 in the compound. In Cu+2, the electronic configuration would be

1s22s22p63s23p63d94s0

So, there would be a rearrangement of electrons in Cu2+ because of the NH3 ligand (which is a strong one). And the last electron in the d-orbital would be out waiting for the N's electrons to fill up first.

Cu(NH3)4]^2 + shows the following hybridization
ctaimg
background image

Get Expert Academic Guidance – Connect with a Counselor Today!

+91
whats app icon