‘sp²d’ hybridization is observed in

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

[Cu(NH₃)₄]SO₄

K₂[NiCl₄]

Na₂[CuCl₄]

K₂[Ni(CN)₄]

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

The hybridization should be dsp².

The Cu atom is in form of Cu⁺² in the compound. In Cu⁺², the electronic configuration would be

1s²2s²2p⁶3s²3p⁶3d⁹4s⁰

So, there would be a rearrangement of electrons in Cu²⁺ because of the NH₃ ligand (which is a strong one). And the last electron in the d-orbital would be out waiting for the N's electrons to fill up first.

Cu(NH3)4]^2 + shows the following hybridization

Watch 3-min video & get full concept clarity

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!