‘sp2d’ hybridization is observed in

The hybridization should be dsp2.The Cu atom is in form of Cu+2 in the compound. In Cu+2, the electronic configuration would be1s22s22p63s23p63d94s0So, there would be a rearrangement of electrons in Cu2+ because of the NH3 ligand (which is a strong one). And the last electron in the d-orbital would be out waiting for the N's electrons to fill up first.

‘sp2d’ hybridization is observed in

The hybridization should be dsp2.The Cu atom is in form of Cu+2 in the compound. In Cu+2, the electronic configuration would be1s22s22p63s23p63d94s0So, there would be a rearrangement of electrons in Cu2+ because of the NH3 ligand (which is a strong one). And the last electron in the d-orbital would be out waiting for the N's electrons to fill up first.

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‘sp²d’ hybridization is observed in

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[Cu(NH₃)₄]SO₄

K₂[NiCl₄]

Na₂[CuCl₄]

K₂[Ni(CN)₄]

answer is A.

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Detailed Solution

The hybridization should be dsp².

The Cu atom is in form of Cu⁺² in the compound. In Cu⁺², the electronic configuration would be

1s²2s²2p⁶3s²3p⁶3d⁹4s⁰

So, there would be a rearrangement of electrons in Cu²⁺ because of the NH₃ ligand (which is a strong one). And the last electron in the d-orbital would be out waiting for the N's electrons to fill up first.