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Q.

‘sp2d’ hybridization is observed in

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a

[Cu(NH3)4]SO4

b

K2[NiCl4]

c

Na2[CuCl4]

d

K2[Ni(CN)4]

answer is A.

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Detailed Solution

The hybridization should be dsp2.

The Cu atom is in form of Cu+2 in the compound. In Cu+2, the electronic configuration would be

1s22s22p63s23p63d94s0

So, there would be a rearrangement of electrons in Cu2+ because of the NH3 ligand (which is a strong one). And the last electron in the d-orbital would be out waiting for the N's electrons to fill up first.

Cu(NH3)4]^2 + shows the following hybridization
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‘sp2d’ hybridization is observed in