${\mathrm{sp}}^3{\mathrm{d}}^2$ hybridization is not displayed by

${\mathrm{sp}}^3{\mathrm{d}}^2$ hybridization is not displayed by ${\mathrm{PF}}_5$. The central P atom has 5 sets of electron pairs (all of which are bonding) and ${\mathrm{sp}}^3{\mathrm{d}}^2$ hybridization corresponds to 6 sets of electron pairs.

Hence, the correct option is (A)