Q.

Specific conductance of 0.1M CH3COOH at 25°C is 3.9×10-4 ohm-1 cm-1if λ(H3O+) & λ(CH3COO-)  at 25°C  are 349.0 and 41.0 ohm-1 cm2mol-1 respectively degree of ionization of CH3COOH at the given concentration is

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a

5.0%

b

4.0%

c

1.0%

d

2.0%

answer is A.

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Detailed Solution

λCH3COOH=λCH3COO-+λH+

=349+41

=390

λM=K×1000M=3.9×10-4×10000.1

λM=3.9

% α =λMλM0=3.9390×1000=1%

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