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Q.

Specific conductivity of 0.01M solution of HX is $10^{- 6} mho {cm}^{- 1}$ . Molar conductance of the solution is equal to $X mho {cm}^{2} {mole}^{- 1} .$ Value of ‘X’ is equal to

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a

0.1

b

1

c

0.01

d

0.001

answer is A.

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Detailed Solution

$λ_{m}^{} = \frac{k \times 1000}{M}; λ_{m} (mho {cm}^{2} {mole}^{- 1}) = \frac{10^{- 6} (mho {cm}^{- 1}) \times 1000}{0.01 M} = 10^{- 1}$

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