Specific gravity of a body is numerically equal to

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weight of the body in air

relative density of the body

density of body in water

weight of the body in water

answer is C.

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Detailed Solution

Specific gravity of a body is defined as ratio of weight of body in air to the loss of weight of body in water at 4°C. $= \frac{V s g}{V s w g} = \frac{s}{s w} = R e l a t i v e d e n s i t y o f t h e b o d y .$

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