Specific gravity of commercial sulphuric acid is 1.8 and it is 98% pure. Volume of this acid required for preparing 7.2 litres of decinormal sulphuric acid is

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72 ml

10 ml

4 ml

20 ml

answer is B.

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Detailed Solution

$\begin{array}{l} N = \frac{% \times s p e c i f i c g r a v i t y \times 10}{G E W} = \frac{98 % \times 1.8 \times 10}{49} = 36 \\ N_{1} V_{1} = N_{2} V_{2} \\ 36 \times V_{1} = 0.1 \times 7.2 \\ V_{1} = \frac{7.2 \times 0.1}{36} = 0.022 \\ V_{1} = 20 m l \end{array}$

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