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Q.

Specific heats of one mole of hydrogen at constant pressure and at constant volume are 450 JK-1 and
300JK-1, respectively. Then, what is the density of the gas at STP? (Take, ρatm = 1.013 X 105 Nm-2) 

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a

4 kgm-3

b

2.47 kg m-3

c

3.58 kg m-3

d

3kgm-3

answer is A.

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Detailed Solution

Given,  Cp=450JK−1 and CV=300JK−1

∴ Cp−CV=R

⇒ R=450−300=150JK−1

At STP,       T = 273K

p=patm=1.013×105Nm−2

From ideal equation of gas,

 pV=nRT

⇒ pMρ=MmRT

⇒ ρ=pmRT

ρ=1.013×105×1150×273

 or  ρ=2.47kg/m3

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