Speed of electron in Bohr’s 7th orbit for hydrogen atom is 3.6×106m/s. The corresponding speed of the electron in 3rd orbit, in m/s is:

Speed of electron in orbit V =2.18×106Znm/s3.6×106=2.18×1067Z73×3.6×106=2.18×106Z38.4×106m/s

Speed of electron in Bohr’s 7th orbit for hydrogen atom is 3.6×106m/s. The corresponding speed of the electron in 3rd orbit, in m/s is:

Speed of electron in orbit V =2.18×106Znm/s3.6×106=2.18×1067Z73×3.6×106=2.18×106Z38.4×106m/s

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Speed of electron in Bohr’s 7^th orbit for hydrogen atom is $3.6 \times 10^{6} m / s .$ The corresponding speed of the electron in 3rd orbit, in m/s is:

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$(1.8 \times 10^{6})$

$(3.6 \times 10^{6})$

$(7.5 \times 10^{6})$

$(8.4 \times 10^{6})$

answer is D.

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Detailed Solution

Speed of electron in orbit V $= 2.18 \times 10^{6} \frac{Z}{n} m / s$
$3.6 \times 10^{6} = \frac{2.18 \times 10^{6}}{7} Z$
$\begin{array}{l} \frac{7}{3} \times 3.6 \times 10^{6} = \frac{2.18 \times 10^{6} Z}{3} \\ 8.4 \times 10^{6} m / s \end{array}$