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spherical shell of radius R = 1.5 cm has a charge q = 20 $μ$ C uniformly distributed over it. The force exerted by one half over the other half is

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zero

$10^{- 2} N$

500 N

2000 N

answer is D.

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Detailed Solution

Force = $p π R^{2} = \frac{σ^{2}}{2 ε_{0}} π R^{2}$

$= \frac{Q^{2}}{16 π^{2} R^{4}} \frac{π R^{2}}{2 ε_{0}} = \frac{Q^{2}}{32 π ε_{0} R^{2}}$ $= \frac{{(20 \times 10^{- 6})}^{2} \times 9 \times 10^{9}}{8 {(1.5 \times 10^{- 2})}^{2}} = 2000 N$

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