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Q.

Spin only magnetic moment of V3+ is equal to

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a

2.82 B.M

b

3.87 B.M

c

5.9 B.M

d

1.732 B.M

answer is B.

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Detailed Solution

Step-by-Step Explanation:

To calculate the magnetic moment of the V3+ ion, we need to use the formula for magnetic moment:

 μ = √[n(n + 2)] B.M.
 

Where n is the number of unpaired electrons.

Oxidation State of V:

V (Vanadium) has an atomic number of 23.

V3+ means that the Vanadium atom has lost 3 electrons, so its electron configuration will be:

V3+: [Ar] 3d2

This means there are 2 unpaired electrons in the 3d orbital.

Using the formula μ = √[n(n + 2)], where n = 2 (the number of unpaired electrons):

 μ = √[2(2 + 2)] = √[2 × 4] = √8 = 2.828 B.M.
 

Final Answer

The magnetic moment of V3+ is approximately 2.82 B.M.

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