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Split 150 into three parts provided that the second number is $56$ times the primary and also the third number is $45$ time the second.

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40, 50, 60

60, 50, 40

50, 40, 60

40, 60, 50

answer is B.

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Detailed Solution

Given number is 150 and it split into three parts.
The second number is

56

times the primary and also the third number is

45

time the second.
Let first number be

' n'

.
According to the question,
Second number

= 56 n

-(i)
Third number

= 45 56 n

Third number

= 46 n

-(ii)
We know,

Taking L.C.M. on L.H.S.

⇒ 6 n + 5 n + 4 n 6 = 150 ⇒ 15 n 6 = 150

After Cross-multiplication,

n = 150 × 6 15 n = 10 × 6 n = 60

First number is 60.
Substituting value of

' n'

in (i) & (ii):
Second number,

⇒ 56 n

⇒ 56 × 60

⇒ 5 × 10

⇒

50
Second number is 50.
Third number,

⇒ 46 n

⇒ 46 × 60 ⇒ 4 × 10 ⇒ 40

Third number is 40.
The number 150 is split into 60, 50, 40.
Hence, option 2 is correct.

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