Here, the given figures can be further divided into rectangles,
We know that, Area of the rectangle = length × breadth
and the Area of the square = length × length
(a) Here, the area of the rectangle I = 10 cm × 2 cm = 20 sq. cm
Here, the area of the rectangle II = 10 cm × 2 cm = 20 sq. cm
The total area of the figure is therefore equal to the sum of the area of the two rectangles.
= 20 sq. cm + 20 sq. cm = 40 sq. cm.
(b) Here, the area of the square I = 7 cm × 7 cm = 49 sq. cm
Here, the area of the square II = 7 cm × 7 cm = 49 sq. cm
Here, the area of the square III = 7 cm × 7 cm = 49 sq. cm
Here, the area of the square IV = 7 cm × 7 cm = 49 sq. cm
Here, the area of the square V = 7 cm × 7 cm = 49 sq. cm
The total area of the figure is therefore equal to the sum of the area of the rectangles and two squares.
= 49 sq. cm + 49 sq. cm + 49 sq. cm + 49 sq. cm + 49 sq. cm = 245 sq. cm.
(c) Here, the area of the rectangle I = 5 cm × 1 cm = 5 sq. cm
Here, the area of the rectangle II = 4 cm × 1 cm = 4 sq. cm
The total area of the figure is therefore equal to the sum of the area of the two rectangles.
= 5 sq. cm + 4 sq. cm = 9 sq. cm.
