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Q.

Stability of the species Li2, Li2 and Li2+ increases in the order of :

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a

Li2 < Li2+ < Li2

b

Li2 < Li2+ < Li2

c

Li2 < Li2 < Li2+

d

Li2 < Li2 < Li2+

answer is D.

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Detailed Solution

Li2 = kkσ2s2

 

Bond order =4-22=1
Li+2 kkσ2s1Bond order = 3-22=0.5
Li2-=kkσ2s2σ2s*14-32=0.5

Bond order = Li2 > Li+2 = Li

stability order  Li2>Li2+>Li2-

when two molecular species have same bond order then the species with maximum number of electrons in antibonding molecular orbitals is less stable.

 Number of ABMO electrons in Li2-= 3

Number of ABMO electrons in  Li2+= 2

stability\,\,of\,\,Li^ - _2 < \,\,Li_2 ^ +
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