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Q.

Standard enthalpies of formation carbon dioxide, water and acetylene are -390, -286 and +254 kJ/molerespectively.

Enthalpy of combustion of acetylene is equal to…..kJ/mole

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a

-1410

b

-1530

c

-1260

d

-1320

answer is D.

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Detailed Solution

Given,

Cgraphite+O2gCO2g,    H=-390 kJ/mole....1 H2g+12O2gH2O l,           H=-286 kJ/mole....2 2Cgraphite+H2gC2H2g, H=+254 kJ/mole....3 Required equation is C2H2g+52O2g2CO2g+H2Ol          2× Eq1+Eq2-Eq3=Required equation       2-390+-286-+254=Required equation                       -780-286-254=Required equation                                     c0(C2H2)=-1320 kJ/mole 

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